Answers Logo
Search


Who Will Be the Leader in Monetizing Social Media?



Facebook

Twitter

Apple (Mobile Applications)

A different company

There will be no one leader

Vote

Share/Save/Bookmark
View The Results of This Poll



rss
3 Comments
2009-03-29 22:09:07 ET

What about MySpace (Fox Interactive Media)? They are teh only social media company currently making a handsome profit!

2009-03-30 13:33:52 ET

I think monetization will come from startups such as BidWilly.com. They have found a way to leverage social sites in order to build relationships between consumers and service providers when conducting business. I also love their strategy around open-bidding as it gives consumers the power to do more with less while providing an inexpensive way for service providers to reach prospective consumers.

Michael
2009-03-30 20:07:40 ET

For this article to be taken seriously and not look so biased Myspace should have been mentioned. Apple, as admitted in the article is not a social media company though was included, but not Myspace. The previous leader in the social site set, just a few months removed if that and the one that is still the money king where these sites are concerned, but they don't get a mention. That is either very poor journalism, or wishful thinking and unadulterated bias.


Leave a comment

Email Address *

Your email address will not be published. (We add your Gravatar icon if you have one)

Please enter a valid email address below.

Name *

Please enter your name below.

Your Website URL

Comment *

Maximum of 4000 chars. (0/4000)

Please enter a comment below.

(Fields marked * are mandatory)


Submit Comment
Spam controlled by Akismet

Poll Author

Founded in July 2005, Mashable is the world’s largest blog focused exclusively on Web 2....

View My Previous Polls

My Website

Share Link

Use the link below to share this poll.

Embed This Poll

You can also place this poll on your website or blog as a widget. Simply copy and paste the code below into your HTML.

Alternatively, we now support oEmbed.